This is a **precipitation** reaction: **SrSO4** is the formed precipitate.

### Word equation

* strontium nitrate + sulfuric acid → strontium sulfate + nitric acid*

### Input interpretation

* Sr(NO3)2 + H2SO4 → SrSO4 + HNO3*

* Strontium nitrate sulfuric acid strontium sulfate nitric acid*

### Balanced equation

Balance the chemical equation algebraically:

* Sr(NO3)2 + H2SO4 → SrSO4 + HNO3*

Add stoichiometric coefficients, c, to the reactants and products:

* Sr(NO3)2 + H2SO4 → SrSO4 + HNO3*

Set the number of atoms in the reactants equal to the number of atoms in the products for ** N, O, Sr, H **and

*S:**N: 2c1 = c4*

*O: 6c + 4c2 = 4c3 + 3c4*

*Sr: c1 = c3*

* H: 2c2 = c4*

*S: c2 = c3*

Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set** c1 = 1** and solve the system of equations for the remaining coefficients:

* c1=1 c2 = 1*

* c3 = 1 c4=2*

Substitute the coefficients into the chemical reaction to obtain the balanced equation:

**Answer**:

* Sr(NO3)2 + H2SO4 → SrSO4 + HNO3*