This is a precipitation reaction: SrSO4 is the formed precipitate.
Word equation
strontium nitrate + sulfuric acid → strontium sulfate + nitric acid
Input interpretation
Sr(NO3)2 + H2SO4 → SrSO4 + HNO3
Strontium nitrate sulfuric acid strontium sulfate nitric acid
Balanced equation
Balance the chemical equation algebraically:
Sr(NO3)2 + H2SO4 → SrSO4 + HNO3
Add stoichiometric coefficients, c, to the reactants and products:
Sr(NO3)2 + H2SO4 → SrSO4 + HNO3
Set the number of atoms in the reactants equal to the number of atoms in the products for N, O, Sr, H and S:
N: 2c1 = c4
O: 6c + 4c2 = 4c3 + 3c4
Sr: c1 = c3
H: 2c2 = c4
S: c2 = c3
Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c1 = 1 and solve the system of equations for the remaining coefficients:
c1=1 c2 = 1
c3 = 1 c4=2
Substitute the coefficients into the chemical reaction to obtain the balanced equation:
Answer:
Sr(NO3)2 + H2SO4 → SrSO4 + HNO3
