This is an oxidation-reduction (redox) reaction:
10 F0 + 10 e- → 10 F-I (reduction)
2 N-III - 10 e- → 2 NII (oxidation)
F2 is an oxidizing agent, NH3 is a reducing agent
.
Word equation
fluorine + ammonia → tetrafluorohydrazine + hydrogen fluoride
Input interpretation
F2 + NH3 → F4N2 + HF
Fluorine ammonia tetrafluorohydrazine hydrogen fluoride
Balanced equation
Balance the chemical equation algebraically:
F2 + NH3 → F4N2 + HF
Add stoichiometric coefficients, c, to the reactants and products:
c1F2 + c2NH3 → c3F4N2 + c4HF
Set the number of atoms in the reactants equal to the number of atoms in the products for F, H and N:
F: 2c1 = 4c3 + c4
H: 3c2 = c4
N: c2=2c3
Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c3 = 1 and solve the system of equations for the remaining coefficients:
c1=5 c2=2
c3=1 c4=6
Substitute the coefficients into the chemical reaction to obtain the balanced
equation:
Answer:
F2 + NH3 → F4N2 + HF
