This is an **oxidation-reduction** (redox) reaction:

* 10* **F**0 + *10* **e**- → *10* **F**-I *(reduction)*

* 2* **N**-III - *10* **e**- → *2* **N**II *(oxidation)*

** F2** is an

**oxidizing**agent,

**is a**

*NH3***reducing**agent

.

### Word equation

* fluorine + ammonia → tetrafluorohydrazine + hydrogen fluoride*

### Input interpretation

* F2 + NH3 → F4N2 + HF*

* Fluorine ammonia tetrafluorohydrazine hydrogen fluoride*

### Balanced equation

Balance the chemical equation algebraically:

* F2 + NH3 → F4N2 + HF*

Add stoichiometric coefficients, c, to the reactants and products:

* c1F2 + c2NH3 → c3F4N2 + c4HF*

Set the number of atoms in the reactants equal to the number of atoms in the products for** F, H **and

*N:**F: 2c1 = 4c3 + c4*

*H: 3c2 = c4 *

*N: c2=2c3*

Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set ** c3 = 1** and solve the system of equations for the remaining coefficients:

* c1=5 c2=2*

* c3=1 c4=6*

Substitute the coefficients into the chemical reaction to obtain the balanced

equation:

**Answer**:

* F2 + NH3 → F4N2 + HF*