This is an acid-base reaction (neutralization): HF is an acid, Ba(OH)2 is a base.
This is a precipitation reaction: BaF2 is the formed precipitate.
Word equation
hydrogen fluoride + barium hydroxide → water + barium fluoride
Input interpretation
HF + Ba(OH)2 → H2O + BaF2
Hydrogen fluoride barium hydroxide water barium fluoride
Balanced equation
Balance the chemical equation algebraically:
HF + Ba(OH)2 → H2O + BaF2
Add stoichiometric coefficients, c,, to the reactants and products:
c1HF + c2Ba(OH)2 → c3H2O + c4BaF2
Set the number of atoms in the reactants equal to the number of atoms in the products for F, H, Ba and O:
F: c1 = 2c4
H: c1+ 2c2 = 2c3
Ba: c2 = c4
0: 2c2 = c3
Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c2 = 1 and solve the system of equations for the remaining coefficients:
c1 = 2 c2=1
c3=2 c4=1
Substitute the coefficients into the chemical reaction to obtain the balanced
equation:
Answer:
HF + Ba(OH)2 → H2O + BaF2
