This is an **oxidation-reduction** (redox) reaction:

* 2 Br-I - 2 e- → 2 Br0 (oxidation)*

* CuII + 2 e- → Cu0 (reduction)*

*CuBr2* is a **reducing** agent, *CuBr2* is an **oxidizing** agent.

### Word equation

* cupric bromide → copper + bromine*

### Input interpretation

* CuBr2 → Cu + Br2*

* cupric bromide copper bromine*

### Balanced equation

Balance the chemical equation algebraically:

* *

* CuBr2 → Cu + Br2*

Add stoichiometric coefficients, c, to the reactants and products:

* c1 CuBr2 → c2Cu + c3Br2*

Set the number of atoms in the reactants equal to the number of atoms in the products for ** Br **and

*Cu:**Br: 2c1 = 2c3*

*Cu: c1=c2*

Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c1 = 1 and solve the system of equations for the remaining coefficients:

* c1 = 1 c2=1 *

* c3 = 1*

Substitute the coefficients into the chemical reaction to obtain the balanced

equation:

Answer:

* *

* CuBr2 → Cu + Br2*