This is an oxidation-reduction (redox) reaction:
Al0 - 3 e- → AlIII (oxidation)
3 O-I + 3 e- → 3 O-II (reduction)
Al is a reducing agent, OH is an oxidizing agent.
Word equation
Al(OH)3 → Al(OH)3
aluminum hydroxide → aluminum hydroxide
Input interpretation
Al(OH)3 → Al(OH)3
aluminum hydroxide
Balanced equation
Balance the chemical equation algebraically:
Al(OH)3 → Al(OH)3
Add stoichiometric coefficients, c1 to the reactants and products:
c1Al(OH)3 → c2 Al(OH)3
Set the number of atoms in the reactants equal to the number of atoms products for Al, H and O:
Al: c1= c2
H: 3c1 = 3 c2
O: 3c1=3 c2
Since the coefficients are relative quantities and underdetermined, choose coefficients to set arbitrarily. To keep the coefficients small, the arbitrary ordinarily one. For instance, set c1= 1 and solve the system of equation remaining coefficients: c2 = 1
Substitute the coefficients into the chemical reaction to obtain the balance equation:
Answer:
Al(OH)3→ Al(OH)3
