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This is an oxidation-reduction (redox) reaction:

Al0 - 3 e- → AlIII (oxidation)

3 O-I + 3 e- → 3 O-II (reduction)

Al is a reducing agent, OH is an oxidizing agent.

Word equation

Al(OH)3 → Al(OH)3

aluminum hydroxide → aluminum hydroxide

Input interpretation

Al(OH)3 → Al(OH)3

aluminum hydroxide

Balanced equation

Balance the chemical equation algebraically:

Al(OH)3 → Al(OH)3

Add stoichiometric coefficients, c1 to the reactants and products: 

c1Al(OH)3 c2 Al(OH)3

Set the number of atoms in the reactants equal to the number of atoms products for Al, H and O:

Al: c1= c2

H: 3c1 = 3 c2

O: 3c1=3 c2

Since the coefficients are relative quantities and underdetermined, choose coefficients to set arbitrarily. To keep the coefficients small, the arbitrary ordinarily one. For instance, set c1= 1 and solve the system of equation remaining coefficients: c2 = 1

Substitute the coefficients into the chemical reaction to obtain the balance equation:


 Al(OH)3→ Al(OH)3