# nahso3

Sodium bisulfite is a chemical mixture with the approximate chemical formula NaHSO₃. Sodium bisulfite in fact is not a real compound.

Sarah Taylor-

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Sodium bisulfite (NaHSO3) is a reducing agent and undergoes oxidation-reduction (redox) reaction with chlorine (Cl2) which is an oxidizing agent. The balanced chemical equation for this reaction is:

## Input interpretation:

NaHSO3 + Cl2 + H2O → NaHSO4 + HCl

This equation can be broken down into the following steps:

Oxidation: Sulfur in NaHSO3 undergoes oxidation and gains an oxygen atom to form sulfate (SO4) ion. This can be represented as:

SIV - 2 e- → SVI

Reduction: Chlorine gains an electron to form chloride (Cl-) ion. This can be represented as:

2 Cl0 + 2 e- → 2 Cl-I

## Balanced equation:

Step 1: Add stoichiometric coefficients, c, to the reactants and products:

c1NaHSO3 + c2Cl2 + c3H2O → c4NaHSO4 + c5HCl

Step 2: Set the number of atoms in the reactants equal to the number of atoms in the products for H, Na, O, S, and Cl:

H: c1 + 2c3 = c4 + c5

Na: c1 = c4

O: 3c1 + c3 = 4c4

S: c1 = c4

Cl: 2c2 = c5

Step 3: Choose an arbitrary value to set the coefficients. For instance, set c1 = 1 and solve the system of equations for the remaining coefficients:

c1 = 1

c2 = 1

c3 = 1

c4 = 1

c5 = 2

Step 4: Substitute the coefficients into the chemical reaction to obtain the balanced equation:

NaHSO3 + Cl2 + H2O → NaHSO4 + HCl

In summary, sodium bisulfite reacts with chlorine to form sodium bisulfate and hydrogen chloride in a redox reaction. This balanced equation is useful for understanding the stoichiometry and quantities of reactants and products involved in this reaction.