This is an **acid-base** reaction (*neutralization*): *NaOH* is a **base**, *H2SO4* is an **acid**.

### Word equation

* sodium hydroxide + sulfuric acid → water + sodium sulfate*

### Input interpretation

* NaOH + H2SO4 → H2O + Na2SO4*

* Sodium hydroxide sulfuric acid water sodium sulfate*

### Balanced equation

Balance the chemical equation algebraically:

* NaOH + H2SO4 → H2O + Na2SO4*

Add stoichiometric coefficients, c, to the reactants and products:

* c1NaOH + c2 H2SO4 → c3H2O + c4Na2SO4*

Set the number of atoms in the reactants equal to the number of atoms in the products for **H, Na, O **and **S:**

*H: c1 + 2c2 = 2c3*

*Na: c1 = 2c4*

*O: c1 + 4c2 = c3 + 4c4*

*S: c2=c4*

Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set **c2 = 1** and solve the system of equations for the remaining coefficients:

* C1 = 2 C2=1*

* C3=2 C4=1*

Substitute the coefficients into the chemical reaction to obtain the balanced equation:

Answer:

* NaOH + H2SO4 → H2O + Na2SO4*