This is an acid-base reaction (neutralization): HI is an acid, KOH is a base.
Word equation
hydrogen iodide + potassium hydroxide → potassium iodide + water
Input interpretation
HI + KOH → KI + H2O
Hydrogen iodide potassium hydroxide potassium iodide water
Balanced equation
Balance the chemical equation algebraically:
HI + KOH → KI + H2O
Add stoichiometric coefficients, c,, to the reactants and products:
c1 HI + c2 KOH → c3 KI + c4 H2O
Set the number of atoms in the reactants equal to the number of atoms in the products for H, I, K and O:
H: c1 + c2 = 2c4
I: c1 = c3
K: c2 = c3
O: c2 = c4
Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c1 = 1 and solve the system of equations for the remaining coefficients:
c1 = 1 c2=1
c3 = 1 c4=1
Substitute the coefficients into the chemical reaction to obtain the balanced equation:
Answer:
HI + KOH → KI + H2O
Word equation
hydrogen iodide + potassium hydroxide → potassium iodide + water
