N-Propanol, also known as 1-propanol, is an alcohol with the chemical formula CH3CH2CH2OH. When it reacts with potassium permanganate (KMnO4) and sulfuric acid (H2SO4), it undergoes an oxidation-reduction (redox) reaction.

The balanced chemical equation for this reaction is:

CH3CH2CH2OH + 2KMnO4 + 3H2SO4 → CH3COCH3 + 2MnSO4 + 8H2O + K2SO4

In this equation, KMnO4 is the oxidizing agent, while N-Propanol (CH3CH2CH2OH) is the reducing agent.

## Input Interpretation:

N-Propanol (CH3CH2CH2OH) + Potassium permanganate (KMnO4) + Sulfuric acid (H2SO4) → Acetone (CH3COCH3) + Manganese(II) sulfate (MnSO4) + Water (H2O) + Potassium sulfate (K2SO4)

## Word Equation:

N-Propanol + Potassium permanganate + Sulfuric acid → Acetone + Manganese(II) sulfate + Water + Potassium sulfate

## Balancing the Equation:

To balance the equation, we need to add stoichiometric coefficients (c) to the reactants and products. Then, we set the number of atoms in the reactants equal to the number of atoms in the products for C, H, O, K, Mn, and S.

After setting an arbitrary value (usually 1) for one of the coefficients, we can solve the system of equations for the remaining coefficients. For this equation, we can set c7 = 1 and obtain the following coefficients:

c1 = 5

c2 = 2

c3 = 3

c4 = 5

c5 = 2

c6 = 8

Substituting these coefficients into the chemical equation, we obtain the balanced equation shown above.