Br2O is a chemical compound with both oxidizing and reducing properties, known as disproportionation (dismutation). In the reaction below, it reacts with sodium hydroxide to form sodium bromate, sodium bromide, and water.

Input interpretation:

Br2O + NaOH → NaBrO + NaBr + H2O

Balanced equation:

To balance this chemical equation, we use an algebraic balancing method. Here's how it's done:

Step 1: Write the unbalanced equation and assign stoichiometric coefficients to each compound.

Br2O + NaOH → NaBrO + NaBr + H2O

c1Br2O + c2NaOH → c3NaBrO + c4NaBr + c5H2O

Step 2: Set the number of atoms of each element in the reactants equal to the number of atoms of the same element in the products.

Br: 2c1 = c3 + c4

O: c1 + c2 = 3c3 + c5

H: c2 = 2c5

Na: c2 = c3 + c4

Step 3: Choose an arbitrary value (usually 1) for one of the coefficients, and solve the system of equations for the remaining coefficients.

Assuming c3 = 1:

c1 = 3/2

c2 = 3

c4 = 2

c5 = 3/2

c3 = 1

Step 4: Multiply all coefficients by the least common denominator (2 in this case) to eliminate any fractional coefficients.

c1 = 3

c2 = 6

c3 = 2

c4 = 4

c5 = 3

The balanced chemical equation is:

3Br2O + 6NaOH → 2NaBrO + 4NaBr + 3H2O

In conclusion, when Br2O reacts with NaOH, it produces NaBrO, NaBr, and H2O, and the balanced chemical equation for the reaction is 3Br2O + 6NaOH → 2NaBrO + 4NaBr + 3H2O. This information is important for understanding the behavior of these compounds in various chemical processes and can be useful in industrial applications.