Boron tribromide, represented by the chemical formula BBr3, is a compound of boron and bromine. It is a colorless to pale yellow fuming liquid that has a pungent odor. The chemical equation for the formation of BBr3 from its constituent elements is as follows:

Word Equation:

boron + bromine → boron tribromide

Input Interpretation:

2B + 3Br2 → BBr3

The above equation represents the combination of two atoms of boron and three molecules of bromine to produce one molecule of BBr3. This equation is an example of an oxidation-reduction (redox) reaction.

Balanced equation:

To balance the chemical equation, we start by adding stoichiometric coefficients, c, to the reactants and products:

2B + 3Br2 → BBr3

We then set the number of atoms of boron (B) and bromine (Br) in the reactants equal to the number of atoms in the products. This gives us the following system of equations:

B: 2c1 = c3

Br: 6c2 = 3c3

Since the coefficients are relative quantities and underdetermined, we choose a coefficient to set arbitrarily. To keep the coefficients small, we set c1 = 1 and solve the system of equations for the remaining coefficients:

c1 = 1

c2 = 1/2

c3 = 2

To eliminate fractional coefficients, we multiply by the least common denominator, 2:

c1 = 2

c2 = 1

c3 = 4

Substituting these coefficients into the chemical reaction, we obtain the balanced equation:

2B + 3Br2 → BBr3

This balanced equation represents the combination of two atoms of boron with three molecules of bromine to form two molecules of BBr3.

In summary, the chemical equation for the formation of boron tribromide is balanced as 2B + 3Br2 → 2BBr3, where Br2 is the oxidizing agent and B is the reducing agent. This equation is essential in understanding the synthesis of BBr3 and can be used to predict the products of similar reactions. As a chemist and SEO specialist, it is essential to have a clear and concise understanding of chemical equations and their balanced forms to accurately convey information to readers and search engines alike.

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